1 1 vote Let$le(x, y) =$ least of x and y (i.e., $\min(x, y))$$me(x, y) =$ maximum of x and y (i.e., $\max(x, y))$$mo(x) = |x|$ (absolute value)Find the value of $me(a + mo(le(a, b)); mo(a + me(mo(a), mo(b)),$ at $a = -2$ and $b = - 3$.$1$ $0$ $5$ $3$ Quantitative Aptitude cat1995 quantitative-aptitude equations multiple-sub-parts + – Misbah Ghaya 8.9k points 1.7k views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
0 0 votes Given that: $a=-2,b=-3$ me(a+mo(le(a,b)); mo(a+me(mo(a);mo(b)) $\implies me(-2+mo(le(-2,-3)); mo(-2+me(mo(-2); mo(-3))$ $\implies me(-2+mo(-3); mo(-2+me(2,3))$ $\implies me(-2+3;mo(-2+3))$ $\implies me(1;1)=1$ Option (A) is correct. Hira Thakur answered Apr 30, 2023 Hira Thakur 6.9k points comment Share Follow 0 reply Please log in or register to add a comment.