Recent questions tagged equations - Aptitude Overflow

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1

CAT1995-67
Refer to the following data: le(x, y) = | least of(x, y) mo(x) = |x| me(x) (x, y) = maximum of(x, y) For what values of $a$ is $le(a^{2} – 3a, a – 3) < 0$? $1 < a < 3$ $a < 0$ and $a < 3$ $a < 0$ and $a < 3$ $a < 0$ or $a < 3$

asked Aug 29, 2017 in Quantitative Aptitude by makhdoom ghaya (7.7k points) | 21 views

+1 vote

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2

CAT1995-66
Refer to the following data: le(x, y) = | least of(x, y) mo(x) = |x| me(x) (x, y) = maximum of(x, y) For what values of a is $me(a^{2} – 3a, a – 3) < 0$? $a < 3$ and $a < 1$ $1 < a < 3$ $a < 3$ or $a < 1$ $a < 3$ or $a < 0$

asked Aug 29, 2017 in Quantitative Aptitude by makhdoom ghaya (7.7k points) | 16 views

+1 vote

0 answers

3

CAT1995-65
Refer to the following data: le(x, y) = | least of(x, y) mo(x) = |x| me(x) (x, y) = maximum of(x, y) Which of the following must be correct? mo(le(a, b)$^{3}$ (me(mo(a), mo(b)) mo(le(a, b)) > (me(mo(a), mo(b)) mo(le(a, b)) < (le(mo(a), mo(b)) mo(le(a, b)) le(mo(a), mo(b))

asked Aug 29, 2017 in Quantitative Aptitude by makhdoom ghaya (7.7k points) | 21 views

+1 vote

0 answers

4

CAT1995-64
Refer to the following data: le(x, y) = | least of(x, y) mo(x) = |x| me(x) (x, y) = maximum of(x, y) Find the value of me(a + mo(le(a, b)); mo(a + me(mo(a), mo(b)), at $a = -2$ and $b = - 3$. $1$ $0$ $5$ $3$

asked Aug 29, 2017 in Quantitative Aptitude by makhdoom ghaya (7.7k points) | 14 views

+1 vote

1 answer

5

CAT1995-55
What is the value of m which satisfies $3m^{2} - 21m + 30 < 0$? $m < 2$, or $m > 5$ $m > 2$ $2 < m < 5$ $m < 5$

asked Aug 28, 2017 in Quantitative Aptitude by makhdoom ghaya (7.7k points) | 24 views

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