CAT 1995 | Question: 66

Question

Refer to the following data:

le(x, y) =  Least of(x, y)

mo(x) = |x|

me(x, y) = maximum of(x, y)

For what values of a is $me(a^{2} – 3a, a – 3) < 0$?

• A. $a >3$
• B. $0 < a < 3$ 
• C. $a < 0$ 
• D. $a =3$

Answer 1

Option (A): $a>3, a=4\rightarrow me(16-12,1)\implies me(4,1)=4 \nless 0$ so it is wrong.

Option (B): $0<a<3; a=2 \implies me(4-6,-1)\implies me(-2,-1)=-2<0$, This condition is satisfy.

Option (C): $a<0;a=-1\implies me(1+3,-4)\implies me(4,-4)=4\nless0$, this is wrong.

Option (D): $a=3\implies me(9-9,0\implies me(0,0)=0\nless 0)$ this is wrong.

Option (B) is correct.