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Option (A): $a>3, a=4\rightarrow me(16-12,1)\implies me(4,1)=4 \nless 0$ so it is wrong.

Option (B): $0<a<3; a=2 \implies me(4-6,-1)\implies me(-2,-1)=-2<0$, This condition is satisfy.

Option (C): $a<0;a=-1\implies me(1+3,-4)\implies me(4,-4)=4\nless0$, this is wrong.

Option (D): $a=3\implies me(9-9,0\implies me(0,0)=0\nless 0)$ this is wrong.

Option (B) is correct.

Option (B): $0<a<3; a=2 \implies me(4-6,-1)\implies me(-2,-1)=-2<0$, This condition is satisfy.

Option (C): $a<0;a=-1\implies me(1+3,-4)\implies me(4,-4)=4\nless0$, this is wrong.

Option (D): $a=3\implies me(9-9,0\implies me(0,0)=0\nless 0)$ this is wrong.

Option (B) is correct.