CAT 2000 | Question: 107
For all non-negative integers $x$ and $y, f(x, y)$ is defined as below $f(0, y) = y + 1$ $f(x + 1, 0) = f(x, 1)$ $f(x + 1,y + 1) = f(x, f(x + 1, y))$ Then, what is the value of $f(1, 2)?$ Two Four Three Cannot be determined
For all non-negative integers $x$ and $y, f(x, y)$ is defined as below$f(0, y) = y + 1$$f(x + 1, 0) = f(x, 1)$$f(x + 1,y + 1) = f(x, f(x + 1, y))$Then, what is the value ...