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If $a, b, c$ and $d$ are four positive real numbers such that $abcd = 1,$ what is the minimum value of $(1 + a)(1 + b)(1 + c)(1 + d)?$

  1. $4$
  2. $1$
  3. $16$
  4. $18$
in Quantitative Aptitude edited by
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Using A.M>=GM

GIVEN abcd=1,

(a+b+c+d)/4=(abcd)^¼

hence a+b+c+d=4.

using this find (1+a)(1+b)(1+c)(1+d) ,which is 16
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