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$ 1 + (4 \times 2) = 9 $

$ 9 + (4 \times 4) = 25 $

$ 25 + (4 \times 6) = 49 $

$ \mathbf{49 + (4 \times 8) = 81} $

$ 81 + (4 \times 10) = 121 $
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Given series is a square of odd numbers;

  • $1^2=1$
  • $3^2=9$
  • $5^2=25$
  • $7^2=49$
  • $9^2=81$
  • $11^2=121$

So option (D) is correct.

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