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Here the letters decrease by 1; the numbers are multiplied by 2.

$(F-1)(2\times2)=E4$

$(E-1)(4\times2)=D8$

$(D-1)(8\times2)=C16$

$(C-1)(16\times2)=B32$

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Alphabets are written in the reverse pattern, the number is in $2^n,n=1,2,3,4….$ that is;

  • $F2\rightarrow F 2^1$
  • $E4\rightarrow (F-1) 2^2$
  • $D8\rightarrow (E-1)2^3$
  • $C16\rightarrow (D-1)2^4$
  • $B32\rightarrow (C-1)2^5$

So the missing term is $E4.$

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