Recent questions tagged algebra

1 votes
1 answer
1
If $c=\dfrac{16 x}{y}+\dfrac{49 y}{x}$ for some non-zero real numbers $x$ and $y,$ then $c$ cannot take the value$-60$ $-50$ $60$ $-70$
1 votes
1 answer
2
If $x_{1} = \;– 1$ and $x_{m} = x_{m+1} + (m + 1)$ for every positive integer $m, $ then $x_{100}$ equals $ – 5151 $$ – 5150 $$ – 5051 $$ – 5050 $
1 votes
1 answer
3
If $\text{a,b,c}$ are non-zero and $14^{a} = 36^{b} = 84^{c},$ then $6b \left( \frac{1}{c} \;– \frac{1}{a} \right)$ is equal to
0 votes
0 answers
4
How many pairs $(a,b)$ of positive integers are there such that $a \leq b$ and $ab = 4^{2017} \; ?$$2017$$2019$$2020$$2018$
2 votes
1 answer
5
2 votes
1 answer
6
For real $\textsf{x}$ , the maximum possible value of $ \frac{x}{\sqrt{1+x^{4}}}$ is $ \frac{1}{\sqrt{3}}$$1$$\frac{1}{\sqrt{2}}$$\frac{1}{2}$
3 votes
1 answer
7
The number of integers that satisfy the equality $\left( x^{2} – 5x + 7 \right)^{x+1} = 1$ is $2$$3$$5$$4$
1 votes
1 answer
8
The number of real$-$valued of the equation $2^{x}+2^{-x}=2-(x-2)^{2}$ isinfinite$1$$0$$2$
1 votes
1 answer
9
How many distinct positive integer-valued solutions exist to the equation $\left ( x^{2}-7x+11 \right )^{(x^{2}-13x+42)} =1$?$6$$8$$2$$4$
2 votes
1 answer
10
1 votes
1 answer
11
If $a, b$ and $c$ are positive integers such that $ab=432, bc=96$ and $c<9,$ then the smallest possible value of $a+b+c$ is$56$$59$$49$$46$
1 votes
1 answer
13
The number of distinct real roots of the equation $\left ( x+\frac{1}{x}\right )^{2}-3\left ( x+\frac{1}{x} \right )+2= 0$ equals
1 votes
1 answer
14
0 votes
1 answer
15
1 votes
1 answer
16
0 votes
1 answer
19
0 votes
1 answer
20
The expression $(11.98\times 11.98 + 11.98 \times x +0.02 \times 0.02)$ will be a perfect square for $x$ equal to:$2.02$$0.17$$0.04$$1.4$
0 votes
1 answer
21
The value of $\large\frac{(0.96)^3-(0.1)^3}{(0.96)^2+0.096+(0.1)^2}$ is :$0.86$$0.95$$0.97$$1.06$
0 votes
1 answer
22
0 votes
2 answers
23
Rs.$6500$ were divided among a certain number of persons. If there had been $15$ more persons, each would have got $Rs.30$ less. Find the original number of persons.$50$$...
0 votes
1 answer
25
The factors of $(x^{2}+4y^{2}+4y-4xy-2x-8)$ are:$(x-2y-4)(x-2y+2)$$(x-y+2)(x-4y-4)$$(x+2y-4)(x+2y+2)$None of these
1 votes
2 answers
26
1 votes
1 answer
27
What is the largest positive integer $n$ such that $\frac{n^{2}+7n+12}{n^{2}-n-12}$ is also a positive integer?$8$$12$$16$$6$
1 votes
1 answer
28
If $5^{x}-3^{y}=13438$ and $5^{x-1}+3^{y+1}=9686$, then $x+y$ equals _______
3 votes
1 answer
29
Given that $x^{2018}y^{2017}=1/2$ and $x^{2016}y^{2019}=8$, the value of $x^2+y^3$ is$35/4$$37/4$$31/4$$33/4$
2 votes
1 answer
30
If $u^2+(u-2v-1)^2=-4v(u+v)$, then what is the value of $u+3v$ ?$1/4$$0$$1/2$$-1/4$
1 votes
1 answer
31
How many different pairs $(a,b)$ of positive integers are there such that $a\leq b$ and $1/a+1/b=1/9$None of these$2$$0$$1$
2 votes
2 answers
32
If $9^{\left ( x-1/2 \right )}-2^{\left ( 2x-2 \right )}=4^{x}-3^{\left (2x-3 \right )}$, then $x$ is$3/2$$2/5$$3/4$$4/9$
1 votes
1 answer
33
If $9^{2x-1}-81^{x-1}= 1944$ then $x$ is$3$$9/4$$4/9$$1/3$
1 votes
1 answer
34
If $x+1= x^{2}$ and $x 0$, then $2x^{4}$ is$6+4\sqrt{5}$$3+5\sqrt{5}$$5+3\sqrt{5}$$7+3\sqrt{5}$
1 votes
1 answer
35
If $a, b, c$ and $d$ are integers such that $a+b+c+d=30$ , then the minimum possible value of $( a-b )^{2}+( a-c )^{2}+( a-d)^{2}$ is $1$$2$$5$$6$
1 votes
1 answer
36
If three positive real numbers $x,y,z$ satisfy $y–x=z–y$ and $xyz = 4$, then what is the minimum possible value of $y$?$2^{(1/3)}$$2^{(2/3)}$$2^{(1/4)}$$2^{(3/4)}$
0 votes
1 answer
37
Let $x<0,\:0<y<1,\:z>1$. Which of the following may be false?$\left (x ^{2} -z^{2}\right )$ has to be positive.$yz$ can be less than one.$xy$ can never be zero.$\left (y ...
2 votes
1 answer
38
If $(5.55)^{x}=(0.555)^{y}=1000$, then the value of $\frac{1}{x}-\frac{1}{y}$ is$3$$1$$\frac{1}{3}$$\frac{2}{3}$
0 votes
1 answer
39
Given $\text{a}$ and $\text{b = a-b; a}$ and $\text{b}$ but $\text{c=a+c-b; a}$ or $\text{b=b-a; a}$ but not $\text{b= a+b}$; find $1$ or $(2$ but not $(3$ or $(4$ and $5...