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Recent questions tagged nielit2016mar-scientistc

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1
NIELIT 2016 MAR Scientist C - Section A: 3
In the first $10$ overs of a cricket game, the run rate was only $3.2$. What should be the run rate in the remaining $40$ overs to reach the target of $282$ runs? $6.25$ $6.5$ $6.75$ $7$
In the first $10$ overs of a cricket game, the run rate was only $3.2$. What should be the run rate in the remaining $40$ overs to reach the target of $282$ runs?$6.25$$6...
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5
NIELIT 2016 MAR Scientist C - Section A: 5
A man walks at $5$ kmph for $6$ hr and at $4$ km/h for $12$ hr. His average speed is $4\frac{1}{3}$ km/h $9\frac{2}{3}$ km/h $9½$ km/h $8$ km/h
A man walks at $5$ kmph for $6$ hr and at $4$ km/h for $12$ hr. His average speed is$4\frac{1}{3}$ km/h$9\frac{2}{3}$ km/h$9½$ km/h$8$ km/h
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NIELIT 2016 MAR Scientist C - Section A: 6
The ratio between the speeds of two trains is $7:8$. If the second train runs $440$kms in $4$hours, then the speed of the first train is: $47.4$ km/hr $57.19$ km/hr $48.13$ km/hr $96.25$ km/hr
The ratio between the speeds of two trains is $7:8$. If the second train runs $440$kms in $4$hours, then the speed of the first train is:$47.4$ km/hr$57.19$ km/hr$48.13$ ...
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9
NIELIT 2016 MAR Scientist C - Section A: 10
If $34$ men completed $2/5$th of a work in $8$ days working $9$ hours a day. How many more man should be engaged to finish the rest of the work in $6$ days working $9$ hours a day? $189$ $198$ $102$ $142$
If $34$ men completed $2/5$th of a work in $8$ days working $9$ hours a day. How many more man should be engaged to finish the rest of the work in $6$ days working $9$ ho...
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2 answers
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NIELIT 2016 MAR Scientist C - Section A: 11
Worker $A$ takes $8$ hours to do a job. Worker $B$ takes $10$ hours to do the same job. How long it take both $\text{A&B}$, working together but independently, to do the same job? $40/9$ days $40/7$ days $7.5$ days $8.5$ days
Worker $A$ takes $8$ hours to do a job. Worker $B$ takes $10$ hours to do the same job. How long it take both $\text{A&B}$, working together but independently, to do the ...
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13
NIELIT 2016 MAR Scientist C - Section A: 12
The expression $(11.98\times 11.98 + 11.98 \times x +0.02 \times 0.02)$ will be a perfect square for $x$ equal to: $2.02$ $0.17$ $0.04$ $1.4$
The expression $(11.98\times 11.98 + 11.98 \times x +0.02 \times 0.02)$ will be a perfect square for $x$ equal to:$2.02$$0.17$$0.04$$1.4$
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NIELIT 2016 MAR Scientist C - Section A: 15
The value of $\large\frac{(0.96)^3-(0.1)^3}{(0.96)^2+0.096+(0.1)^2}$ is : $0.86$ $0.95$ $0.97$ $1.06$
The value of $\large\frac{(0.96)^3-(0.1)^3}{(0.96)^2+0.096+(0.1)^2}$ is :$0.86$$0.95$$0.97$$1.06$
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NIELIT 2016 MAR Scientist C - Section A: 13
$0.04\times 0.0162$ is equal to: $6.48\times 10^{-8}$ $6.48\times 10^{-4}$ $6.48\times 10^{-9}$ $6.48\times 10^{-7}$
$0.04\times 0.0162$ is equal to:$6.48\times 10^{-8}$$6.48\times 10^{-4}$$6.48\times 10^{-9}$$6.48\times 10^{-7}$
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