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Consider the following operators defined below

$x@y$: gives the positive difference of $x$ and $y.$

$x\$y$: gives the sum of squares of $x$ and $y.$

$x₤y$: gives the positive difference of the squares of $x$ and $y.$

$x\&y$:gives the product of $x$ and $y.$

Also, $x,y\:\in\:R\:\text{and}\:x\neq y$. The other standard algebraic operations are unchanged.

The expression $[(x₤y)\div(x@y)]^2-2(x₤y)$ will be equal to

- $x₤y$
- $x\$y$
- $(x₤y)(x@y)$
- Cannot be determined