CAT 2021 Set-2 | Quantitative Aptitude | Question: 18

Question

A person buys tea of three different qualities at ₹$ \; 800,$ ₹ $\; 500,$ and ₹$ \; 300 \; \text{per kg},$ respectively, and the amounts bought are in the proportion $2:3:5.$ She mixes all the tea and sells one-sixth of the mixture at ₹$ \; 700 \; \text{per kg}.$ The price, in $\text{INR per kg},$ at which she should sell the remaining tea, to make an overall profit of $50 \%,$ is

• A. $675$
• B. $653$
• C. $692$
• D. $688$

Answer 1

Let’s draw the table for better understanding.

$$\begin{array}{} & \text{T}_{1} & \text{T}_{2} & \text{T}_{3} \\ \text{Amount per kg:} & ₹ \;800 & ₹ \;500 & ₹ \;300 \\ \text{Quantity:} & \text{2 kg} & \text{3 kg} & \text{5 kg} \\ \text{Total amount} & ₹ \;1600 & ₹ \;1500 & ₹ \;1500  \end{array}$$
Now, we have

• Total amount $ = 1600 + 1500 + 1500 =$ ₹$ \; 4600$
• Total quantity of tea $ = 2 + 3 + 5 = 10 \; \text{kg}$

She mixes all the tea and sells one-sixth of the mixture at ₹$ \; 700 \; \text{per kg.}$

Selling price $ = \frac{10}{6} \times 700  = \frac{7000}{6} =$ ₹ $\; 1166.67$

In order to have an overall profit of $50 \%$ on  ₹ $\; 4600 = 4600 \times \frac{150}{100} =$ ₹ $\; 6900$

Then the selling price of remaining $\left( \frac{50}{6}\right) \text{kg} = 6900 – 1166.67 =$ ₹$ \; 5733.33$

$\therefore$ The price of tea $ = \dfrac{5733.33}{\frac{50}{6}}= \frac{5733.33 \times 6}{50}= \frac{34399.98}{50}  = 687.99 \cong\; $₹ $\; 688.$

Correct Answer $: \text{D}$