2 2 votes If $\log_{2} [3+ \log_{3} \{ 4+ \log_{4} (x-1) \}] – 2 = 0$ then $4x$ equals Quantitative Aptitude cat2021-set2 quantitative-aptitude logarithms numerical-answer + – soujanyareddy13 2.8k points 2.0k views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
1 1 vote Given that, $\log_{2}\left[3+\log_{3}\{4+\log_{4}(x-1)\}\right]-2=0$ $\Rightarrow \log_{2}\left[3+\log_{3}\{4+\log_{4}(x-1)\}\right]=2$ $\Rightarrow 3+\log_{3}\{4+\log_{4}(x-1)\}=2^{2}\quad \left[\because \log_{a}{b} = x \Rightarrow b=a^{x}\right]$ $\Rightarrow \log_{3}\{4+\log_{4}(x-1)\}=1$ $\Rightarrow 4+\log_{4}(x-1)=3^{1}$ $\Rightarrow \log_{4}(x-1)=-1$ $\Rightarrow x-1=4^{-1}$ $\Rightarrow x= \frac{1}{4}+1$ $\Rightarrow \boxed{x= \frac{5}{4}}$ $\therefore$ The value of $4x = 4 \times \frac{5}{4} = 5.$ Correct Answer $:5$ Anjana5051 answered Feb 5, 2022 • edited Feb 13, 2022 by Lakshman Bhaiya Anjana5051 12.1k points comment Share Follow 0 reply Please log in or register to add a comment.