The roots of the equation $x^{2/3}+x^{1/3}-2=0$ are :
Another method, putting $x^{\frac{1}{3}} = y$, so equation will become $y^{2} +y-2 =0$
On solving, we will get values as y = -2 , 1
So, x = $y^{3}$ = $-2^{3}$, $1^{3}$ = -8, 1