1 1 vote If $a^{x}=b$, $b^{y}=c$ and $c^{z}=a$, then the value of $xyz$ is : $0$ $1$ $\frac{1}{3}$ $\frac{1}{2}$ Quantitative Aptitude nielit2019feb-scientistd polynomials + – Lakshman Bhaiya 12.3k points 2.1k views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
0 0 votes $\textrm{Given;}$ $a^{x}=b$, $b^{y}=c$, $c^{z}=a$ $\textrm{Taking log in both side we get:}$ $\Leftrightarrow$ $a^{x}=b$ $\Leftrightarrow$ $\log{a^{x}}$=$\log{b}$ $\Leftrightarrow$ $x.{\log{a}}$=$\log{b}$ $\Leftrightarrow$ $\textrm{$x$ = $\frac{\log{b}}{\log{a}}$}$ $\textrm{In same way}$ $\Leftrightarrow$ $\textrm{$y$ = $\frac{\log{c}}{\log{b}}$}$ $\Leftrightarrow$ $\textrm{$z$ = $\frac{\log{a}}{\log{c}}$}$ $x*y*z$=$\textrm{$\textrm{( $\frac{\log{b}}{\log{a}}$}$)*($\textrm{ $\frac{\log{c}}{\log{b}}$}$ )*($\textrm{$\frac{\log{a}}{\log{c}}$}$ ) }$ $\Leftrightarrow$ $x*y*z$$=$ $1$ Option $B$ is correct. Hira Thakur answered Jun 1, 2020 • edited Mar 27, 2021 by Hira Thakur Hira Thakur 6.9k points comment Share Follow 0 reply Please log in or register to add a comment.