2 votes 2 votes a hollow iron pipe is 21cm long and its external diameter is 8cm. if the thickness of the pipe is 1 cm and iron weigth is 8 g/cm3 then the weigth of the pipe is? Quantitative Aptitude quantitative-aptitude geometry + – gabbar asked Oct 28, 2017 • retagged Dec 12, 2017 by Arjun gabbar 76 points 906 views answer comment Share See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Mass = Density * Volume of the hollow cylinder = 8 * pi * h * (r22 - r12) = 8 * (22/7) * 21 (42 - 32) [ As outer diameter = 8 cm so radius = 4 cm and as thickness of pipe = 1 cm so inner radius = 3 cm ] = 8 * 22 * 3 * 7 = 3.696 kg Habibkhan answered Oct 28, 2017 Habibkhan 1.6k points comment Share See all 0 reply Please log in or register to add a comment.