0 0 votes Let $\text{N} = 55^3 + 17^3 – 72^3.\; \text{N}$ is divisible by both $7$ and $13$ both $3$ and $13$ both $17$ and $7$ both $3$ and $17$ Quantitative Aptitude cat2000 quantitative-aptitude number-systems + – go_editor 14.2k points 1.6k views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
Best answer 2 2 votes Let x=72 and y=17 55 + 17 = 72 Use formula $(x-y)^{3}=x^{3} -y^{3}-3x^{2}y+ 3xy^{2} = x^{3} -y^{3}-3xy(y-x)$ $(72-17)^{3}=72^{3} -17^{3}-3*72*17(17-72)$ $55^{3}+17^{3} -72^{3}=3*72*17*55$ N is divisible by both 3 and 17. Hence,option (4).Both 3 and 17. Leen Sharma answered May 8, 2016 • selected May 14, 2016 by srestha Leen Sharma 11.6k points comment Share Follow 0 reply Please log in or register to add a comment.