Register

CAT 2000 | Question: 95

• edited by
1,017 views

2 Answers

0 votes
0 votes
Given,


x$^2$+y$^2$=0.1

|x–y|=0.2

x$^2$+y$^2$=0.1= (x-y)$^2$-2xy

0.1= 0.04-2xy

-2xy=0.06

xy= – 0.03

Checking the options, |x| and |y| can be 0.1 and 0.3 respectively which adds up to 0.4
User Avatar
Voting & Accepting an answer helps improve the community
← PreviousNext →
← Previous in categoryNext in category →

Related questions

0 votes
0 votes
2 answers
1
go_editor asked Mar 29, 2016
799 views
CAT 2000 | Question: 99
The area bounded by the three curves $|x + y| = 1, |x| = 1$, and $|y| = 1$, is equal to $4$ $3$ $2$ $1$
The area bounded by the three curves $|x + y| = 1, |x| = 1$, and $|y| = 1$, is equal to$4$ $3$$2$$1$
0 votes
0 votes
0 answers
2
go_editor asked Dec 29, 2015
454 views
CAT 2005 | Question: 21
In the $\text{X-Y}$ plane, the area of the region bounded by the graph $|x+y| + |x-y| =4$ is $8$ $12$ $16$ $20$
In the $\text{X-Y}$ plane, the area of the region bounded by the graph $|x+y| + |x-y| =4$ is$8$$12$$16$$20$
0 votes
0 votes
0 answers
4
go_editor asked May 1, 2016
766 views
CAT 2000 | Question: 76
Answer the following question based on the information given below. For real numbers $x, y,$ ... $x$ and $y$ are less than $-1$ Both $x$ and $y$ are positive Both $x$ and $y$ are negative $y > x$
Answer the following question based on the information given below.For real numbers $x, y,$ let$f(x, y) = \left\{\begin{matrix} \text{Positive square-root of}\; (x + y),\...
0 votes
0 votes
0 answers
5
go_editor asked May 1, 2016
454 views
CAT 2000 | Question: 79
Answer the following question based on the information given below. For three distinct real numbers $x, y$ and $z,$ let $f(x, y, z) = \min(\max(x, y), \max(y, z), \max(z, x))$ $g(x, y, z) = \max(\min(x, y), \min(y, z), \min(z, x))$ ... $(h(x, y, z) - f(x, y, z))/(n(x, y, z) - g(x, y, z))$
Answer the following question based on the information given below.For three distinct real numbers $x, y$ and $z,$ let$f(x, y, z) = \min(\max(x, y), \max(y, z), \max(z, x...
Link Copied!