0 0 votes If $a_1 = 1$ and $a_{n+1} = 2a_{n + 5}, n = 1, 2, \dots ,$ then $a_{100}$ is equal to $(5 × 2^99 – 6)$ $(5 × 2^99 + 6)$ $(6 × 2^99 + 5)$ $(6 × 2^99 – 5)$ Quantitative Aptitude cat2000 quantitative-aptitude sequences&series + – go_editor 14.2k points 947 views answer comment Share Follow Print 0 reply Please log in or register to add a comment.