edited by
36 views
0 votes
0 votes

Let $\mathrm{C}$ be the circle $x^{2}+y^{2}+4 x-6 y-3=0$ and $\mathrm{L}$ be the locus of the point of intersection of pair of tangents to $\mathrm{C}$ with the angle between the two tangents equal to $60^{\circ}$. Then, the point at which $\mathrm{L}$ touches the line $x=6$ is

  1. $(6,6)$
  2. $(6,8)$
  3. $(6,4)$
  4. $(6,3)$
edited by

Please log in or register to answer this question.

Answer:

Related questions

0 votes
0 votes
0 answers
1
admin asked Mar 30
65 views
If $x$ and $y$ are real numbers such that $x^{2}+(x-2 y-1)^{2}=-4 y(x+y)$, then the value $x-2 y$ is$1$$2$$-1$$0$
0 votes
0 votes
0 answers
2
admin asked Mar 30
51 views
If $\sqrt{5 x+9}+\sqrt{5 x-9}=3(2+\sqrt{2})$, then $\sqrt{10 x+9}$ is equal to$3 \sqrt{7}$$4 \sqrt{5}$$3 \sqrt{31}$$2 \sqrt{7}$
0 votes
0 votes
0 answers
3
admin asked Mar 30
46 views
Let $n$ be the least positive integer such that $168$ is a factor of $1134^{n}$. If $m$ is the least positive integer such that $1134^{n}$ is a factor of $168^{m}$, then ...
0 votes
0 votes
0 answers
4
admin asked Mar 30
42 views
If $x$ and $y$ are positive real numbers such that $\log _{x}\left(x^{2}+12\right)=4$ and $3 \log _{y} x=1$, then $x+y$ equals$11$$20$$10$$68$
0 votes
0 votes
0 answers
5
admin asked Mar 30
43 views
The number of integer solutions of equation $2|x|\left(x^{2}+1\right)=5 x^{2}$ is