1 1 vote A quadrilateral $A B C D$ is inscribed in a circle such that $A B: C D=2: 1$ and $B C: A D=5: 4$. If $A C$ and $B D$ intersect at the point $E$, then $A E: C E$ equals $2: 1$ $5: 8$ $8: 5$ $1: 2$ Quantitative Aptitude cat2023-set1 quantitative-aptitude geometry + – admin 5.3k points 1.0k views answer comment Share Follow Print 0 reply Please log in or register to add a comment.