Register

CAT 2023 Set-1 | Quantitative Aptitude | Question: 16

• edited by
40 views
0 votes
0 votes
Anil invests Rs. $22000$ for $6$ years in a certain scheme with $4 \%$ interest per annum, compounded half-yearly. Sunil invests in the same scheme for $5$ years, and then reinvests the entire amount received at the end of $5$ years for one year at $10 \%$ simple interest. If the amounts received by both at the end of $6$ years are same, then the initial investment made by Sunil, in rupees, is
• edited by
User Avatar

Please log in or register to answer this question.

Voting & Accepting an answer helps improve the community
← PreviousNext →
← Previous in categoryNext in category →
Answer:

Related questions

0 votes
0 votes
0 answers
1
admin asked Mar 30
64 views
CAT 2023 Set-1 | Quantitative Aptitude | Question: 1
If $x$ and $y$ are real numbers such that $x^{2}+(x-2 y-1)^{2}=-4 y(x+y)$, then the value $x-2 y$ is $1$ $2$ $-1$ $0$
If $x$ and $y$ are real numbers such that $x^{2}+(x-2 y-1)^{2}=-4 y(x+y)$, then the value $x-2 y$ is$1$$2$$-1$$0$
0 votes
0 votes
0 answers
2
admin asked Mar 30
50 views
CAT 2023 Set-1 | Quantitative Aptitude | Question: 2
If $\sqrt{5 x+9}+\sqrt{5 x-9}=3(2+\sqrt{2})$, then $\sqrt{10 x+9}$ is equal to $3 \sqrt{7}$ $4 \sqrt{5}$ $3 \sqrt{31}$ $2 \sqrt{7}$
If $\sqrt{5 x+9}+\sqrt{5 x-9}=3(2+\sqrt{2})$, then $\sqrt{10 x+9}$ is equal to$3 \sqrt{7}$$4 \sqrt{5}$$3 \sqrt{31}$$2 \sqrt{7}$
0 votes
0 votes
0 answers
3
admin asked Mar 30
45 views
CAT 2023 Set-1 | Quantitative Aptitude | Question: 3
Let $n$ be the least positive integer such that $168$ is a factor of $1134^{n}$. If $m$ is the least positive integer such that $1134^{n}$ is a factor of $168^{m}$, then $m+n$ equals $15$ $12$ $24$ $9$
Let $n$ be the least positive integer such that $168$ is a factor of $1134^{n}$. If $m$ is the least positive integer such that $1134^{n}$ is a factor of $168^{m}$, then ...
0 votes
0 votes
0 answers
4
admin asked Mar 30
42 views
CAT 2023 Set-1 | Quantitative Aptitude | Question: 4
If $x$ and $y$ are positive real numbers such that $\log _{x}\left(x^{2}+12\right)=4$ and $3 \log _{y} x=1$, then $x+y$ equals $11$ $20$ $10$ $68$
If $x$ and $y$ are positive real numbers such that $\log _{x}\left(x^{2}+12\right)=4$ and $3 \log _{y} x=1$, then $x+y$ equals$11$$20$$10$$68$
0 votes
0 votes
0 answers
5
admin asked Mar 30
42 views
CAT 2023 Set-1 | Quantitative Aptitude | Question: 5
The number of integer solutions of equation $2|x|\left(x^{2}+1\right)=5 x^{2}$ is
The number of integer solutions of equation $2|x|\left(x^{2}+1\right)=5 x^{2}$ is
Link Copied!