Given that:$\frac{2\sin \theta-\cos \theta}{\cos \theta+\sin \theta}=1$
$\implies2\sin \theta-\cos \theta=\cos \theta +\sin \theta$
$\implies \sin \theta=2\cos \theta$
$\implies \frac{\sin \theta}{\cos\theta}=2$
$\implies \tan \theta=2$
Option (C) is correct.