For two sets $\text{A}$ and $\text{B}$, let $\text{A} \triangle \text{B}$ denote the set of elements which belong to $\text{A}$ or $\text{B}$ but not both. If $\text{P} = \{1,2,3,4\}, \text{Q} = \{2,3,5,6\}, \text{R} = \{1,3,7,8,9\}, \text{S} = \{2,4,9,10\},$ then the number of elements in $(\text{P} \triangle \text{Q}) \triangle (\text{R}\triangle \text{S})$ is $9$ $7$ $6$ $8$
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Mar 20, 2020
in Quantitative Aptitude
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