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Two ships are approaching a port along straight routes at constant speeds. Initially, the two ships and the port formed an equilateral triangle with sides of length $24 \mathrm{km}$. When the slower ship travelled $8 \mathrm{km}$, the triangle formed by the new positions of the two ships and the port became right-angled. When the faster ship reaches the port, the distance, in $\mathrm{km}$, between the other ship and the port will be

  1. $4$
  2. $6$
  3. $12$
  4. $8$
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