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In a triangle $\mathrm{A B C, A B=A C}=8 \mathrm{cm}$. A circle drawn with $\mathrm{BC}$ as diameter passes through $\mathrm{A}$. Another circle drawn with center at $\mathrm{A}$ passes through $\mathrm{B}$ and $\mathrm{C}$. Then the area, in  $\mathrm{sq. cm}$, of the overlapping region between the two circles is

  1. $16(\pi-1)$
  2. $32 \pi$
  3. $32(\pi-1)$
  4. $16 \pi$
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