in Quantitative Aptitude edited by
298 views
0 votes
0 votes

Out of three given numbers, the first one is twice the second and three times the third. If the average of these numbers is $88,$ then the difference between the second and third is :

  1. $24$
  2. $48$
  3. $72$
  4. $96$
in Quantitative Aptitude edited by
13.6k points
298 views

1 Answer

0 votes
0 votes

Let’s assume that first number is $x$, second number is $x/2$ third number is $x/3$.

Now according to the given questions

$\implies\frac{x+\frac{x}{2}+\frac{x}{3}}{3}=88$

$\implies \frac{6x+2x+3x}{6}=88*3$

$\implies 11x=88*18$

$\implies x=144$

therefore

  1. first number =$144$
  2. second number =$72$
  3. third number= $48$

So the difference between the second and third numbers is =$72-48=24$

Option $(A)$ is correct.

6.9k points

Related questions

Quick search syntax
tags tag:apple
author user:martin
title title:apple
content content:apple
exclude -tag:apple
force match +apple
views views:100
score score:10
answers answers:2
is accepted isaccepted:true
is closed isclosed:true