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Let’s assume that first number is $x$, second number is $x/2$ third number is $x/3$.

Now according to the given questions

$\implies\frac{x+\frac{x}{2}+\frac{x}{3}}{3}=88$

$\implies \frac{6x+2x+3x}{6}=88*3$

$\implies 11x=88*18$

$\implies x=144$

therefore

- first number =$144$
- second number =$72$
- third number= $48$

So the difference between the second and third numbers is =$72-48=24$

Option $(A)$ is correct.