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NIELIT 2016 MAR Scientist D: 73

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Given : Perimeter of parallelogram=$50$ cm

            $\Rightarrow 50 = 2(L+B)$        $\left \{ \textbf{Perimeter of Parallelogram = 2(L+B))} \right \}$

            $\Rightarrow {L+B} = {25}….(i)$

Since the length of the parallelogram is $5$ cm more than the width.

            $\Rightarrow {L = B+5}….(ii)$

Put $(ii)\rightarrow(i)$ we get: $2B+5=25\Rightarrow 2B=20\Rightarrow B=10$ cm

Put $B=10$ in $(i)$ we get $L=15$ cm

Option $(A)$ is correct.
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