Lakshman Bhaiya
asked
in Quantitative Aptitude
Apr 3, 2020
recategorized
Nov 4, 2020
by Krithiga2101

676 views
1 vote

Given : Perimeter of parallelogram=$50$ cm

$\Rightarrow 50 = 2(L+B)$ $\left \{ \textbf{Perimeter of Parallelogram = 2(L+B))} \right \}$

$\Rightarrow {L+B} = {25}….(i)$

Since the length of the parallelogram is $5$ cm more than the width.

$\Rightarrow {L = B+5}….(ii)$

Put $(ii)\rightarrow(i)$ we get: $2B+5=25\Rightarrow 2B=20\Rightarrow B=10$ cm

Put $B=10$ in $(i)$ we get $L=15$ cm

Option $(A)$ is correct.

$\Rightarrow 50 = 2(L+B)$ $\left \{ \textbf{Perimeter of Parallelogram = 2(L+B))} \right \}$

$\Rightarrow {L+B} = {25}….(i)$

Since the length of the parallelogram is $5$ cm more than the width.

$\Rightarrow {L = B+5}….(ii)$

Put $(ii)\rightarrow(i)$ we get: $2B+5=25\Rightarrow 2B=20\Rightarrow B=10$ cm

Put $B=10$ in $(i)$ we get $L=15$ cm

Option $(A)$ is correct.