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A man walks $10$ miles at an average rate of $2$ miles per hour and returns on a bicycle at an average rate of $10$ miles per hour. How long (to the nearest hour) does the entire trip take him?

  1. $4$ hours
  2. $5$ hours
  3. $6$ hours
  4. $7$ hours
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He walks $10$ miles at a rate of $2$ miles per hour,

$\therefore$ Time taken by him $= \frac{10}{2} = 5$ hours,

And he returns at a rate of $10$ miles per hour,

Time taken to travel 10 miles back $= 1$ hour

Hence, Total time of entire trip $ = 5+1 = 6$ hours.

(C) is correct.

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