in Quantitative Aptitude recategorized by
457 views
0 votes
0 votes

A dog at point $A$ goes in pursuit of a fox $30$ $m$ away. The dog makes $2$ $m$ and the fox, $1$ m long leaps. If the dog makes two leaps to the fox’s three, at what distance from $A$ will the dog catch up with the fox ?

  1. $100$ $m$
  2. $110$ $m$
  3. $105$ $m$
  4. $120$ $m$
in Quantitative Aptitude recategorized by
12.1k points
457 views

1 Answer

1 vote
1 vote
Relative speed of the dog, $S_r = \dfrac{(2 \times 2m) – (3 \times 1m)}{t},$ where $t$ is the time for two leaps of the dog.  

$\implies S_r = 1m/t$

So, after every $2$ leaps, the dog covers $1m$ distance to the fox. So, to cover $30\;m$ dog will need to make $2 \times 30 = 60$ leaps which will be $2 \times 60 = 120m$.

Correct option: D.
by
8.3k points

Related questions

Quick search syntax
tags tag:apple
author user:martin
title title:apple
content content:apple
exclude -tag:apple
force match +apple
views views:100
score score:10
answers answers:2
is accepted isaccepted:true
is closed isclosed:true