0 0 votes sum of roots of the equation $\dfrac{3x^{3}-x^{2}+x-1}{3x^{3}-x^{2}-x+1}=\dfrac{4x^{3}-7x^{2}+x+1}{4x^{3}+7x^{2}-x-1}$ is : $0$ $1$ $-1$ $2$ Quantitative Aptitude nielit2019feb-scientistc quantitative-aptitude quadratic-equations + – Lakshman Bhaiya 12.3k points 1.9k views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
0 0 votes Answer is C. Applying componendo dividendo rule on both sides. We will get roots as 0,-3,2 Sum of roots = -3 + 2 + 0 = -1 For detailed solution, refer here. https://www.doubtnut.com/question-answer/let-the-root-of-equation-3x3-x2-x-1-3x3-x2-x-14x3-7x2-x-1-4x3-7x2-x-1-be-x1x2x3-then-the-value-of-x1-5983 neethu_seb answered Dec 11, 2022 neethu_seb 3.3k points comment Share Follow 0 reply Please log in or register to add a comment.