# Recent questions tagged straight-lines

1
The image of the point $\left (3, 8 \right)$ in the line $x+3y=7$ is : $\left (1, 4 \right)$ $\left (4, 1 \right)$ $\left (-1, -4 \right)$ $\left (-4, -1 \right)$
The line $x+y=4$ divides the line joining $\text{(-1,1) & (5,7)}$ in the ratio $\lambda : 1$ then the value of $\lambda$ is: $2$ $3$ $\dfrac{1}{2}$ $1$
Let $(x_{1},4),(-2,y_{1})$ lies on the line joining the points $(2,-1),(5,-3)$ then the point $P(x_{1},y_{1})$ lies on the line: $6(x+y)-25=0$ $2x+6y+1=0$ $2x+3y-6=0$ $6(x+y)+25=0$