0 0 votes If $\log _{e}x+\log _{e}(1+x)=0,$ then: $x^{2}+x-1=0$ $x^{2}+x+1=0$ $x^{2}+x-e=0$ $x^{2}+x+e=0$ Quantitative Aptitude nielit2019feb-scientistc logarithms + – Lakshman Bhaiya 12.3k points 2.2k views answer comment Share Follow Print See 1 comment 1 1 comment reply haralk10 838 points commented Apr 21, 2021 reply Follow flag option (A) 0 0 replyShare Please log in or register to add a comment.
1 1 vote option A is right s_dr_13 answered Mar 27, 2022 s_dr_13 228 points comment Share Follow 0 reply Please log in or register to add a comment.
