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NIELIT 2016 DEC Scientist B - Section A: 48

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The present age of father and son at present is $12x$ years and $5x$ years respectively.

Now, $12x – 5x = 28$

$\implies 7x = 28$

$\implies x = 4$

$\therefore $ Father present age $ = 12x = 48$ years and son present age $ = 5x = 20$ years.

Now, the required ratio $ = \dfrac{48+8}{20+8} = \dfrac{56}{28} = \dfrac{2}{1}$

Hence, the ratio of their ages after eight years $ = 2:1.$

So, the correct answer is $(C).$
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