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If the product of three consecutive positive integers is $15600$ then the sum of the squares of these integers is

1. $1777$
2. $1785$
3. $1875$
4. $1877$

Let, the three consecutive positive integers be  $x-1, x$ and $x+1.$

Now, $(x-1)(x )(x+1)=15600$

$\Rightarrow x(x^{2}-1^{2}) =15600$

$\Rightarrow x^{3}-x =15600$

$\Rightarrow x^{3}-x =(25)^{3}-25$

$\Rightarrow \boxed{x =25}$

So,  we can get.

• $x-1=25-1=24$
• $x+1=25+1=26$

$\therefore$ The sum of the squares of these integers $=24^{2}+25^{2}+26^{2}$

$\qquad \qquad = 576+625+676 = 1877.$

Correct Answer $:\text{D}$

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