1 1 vote Let $a_{1},a_{2},a_{3},a_{4},a_{5}$ be a sequence of five consecutive odd numbers. Consider a new sequence of five consecutive even numbers ending with $2a_{3}$. If the sum of the numbers in the new sequence is $450$, then $a_{5}$ is $50$ $51$ $52$ $49$ Quantitative Aptitude cat2017-2 quantitative-aptitude number-systems + – go_editor 14.2k points 1.6k views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
1 1 vote Given that, $a_1,a_2,a_3,a_4,a_5$ are five consecutive odd numbers. $a_3-4,a_3-2,{\color{Red} {a_3}},a_3+2,a_3+4$ A new sequence of five consecutive even numbers ending with $2a_3$ will be : $2a_3-8, 2a_3-6, 2a_3-4,2a_3-2,2a_3$ The sum of the numbers in the new sequence $=450$ $\Rightarrow (2a_3-8)+(2a_3-6)+(2a_3-4)+(2a_3-2)+(2a_3)=450$ $\Rightarrow 10a_3-20 = 450$ $\Rightarrow 10a_3 = 470$ $\Rightarrow \boxed{a_3 = 47}$ $\Rightarrow a_5 = a_3+4=47+4=51.$ Correct Answer $:\text{B}$ Anjana5051 answered Jan 5, 2022 • edited Jan 19, 2022 by Lakshman Bhaiya Anjana5051 12.1k points comment Share Follow 0 reply Please log in or register to add a comment.