0 0 votes Let $f(x)= \dfrac{1}{1+x^2}$ and $g(x)=\dfrac{e^{−x}}{1+[x]}$, where $[x]$ is the greatest integer less than or equal to $x$. Then which of the following domain is true? domain of $(f+g)=R-(-2,-1]$ domain of $(f+g)=R-[-1,0)$ $[\text{range of f}] \cap [\text{range of g}]=\bigg[-2, \dfrac{1}{2} \bigg]$ $[\text{range of f}] \cap [\text{range of g}]= \bigg[- \dfrac{1}{2},\dfrac{1}{2} \bigg]-\{0\}$ Both II and IV Both I and III Both I and IV Both II and III Quantitative Aptitude cat2013 quantitative-aptitude functions + – admin 5.3k points 1.1k views answer comment Share Follow Print 0 reply Please log in or register to add a comment.