+1 vote
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Market shares in four Metropolitan cities.

 Period/ Products Bombay 1993-94 Calcutta 1993-94 Delhi 1993-94 madras 1993-94 HD 20-15 35-30 20-15 20-30 CO 20-25 30-15 15-10 20-15 BN 45-40 25-35 35-35 10-10 MT 15-20 10-20 10-10 50-45

The largest percentage drop in market shares is

1. 60%
2. 50%
3. 53.3%
4. 20%
recategorized | 32 views

+1 vote
Considering only Market drops:

The product $HD$ has experienced a market drop In ${\text{Bombay}}$ $\{(15 - 20) = -5\hspace{0.2cm} i.e \hspace{0.2cm}\dfrac{-5}{20}\times100 = \color{lightblue}{25\%}\}$, $\text{Calcutta}$ $\{(30 - 35) = -5\hspace{0.2cm} i.e \hspace{0.2cm}\dfrac{-5}{35}\times100 = \color{lightblue}{14.28\%}\}$ & $\text{Delhi}$ $\{(15 - 20) = -5\hspace{0.2cm} i.e \hspace{0.2cm}\dfrac{-5}{20}\times100 = \color{lightblue}{25\%}\}$.

The product $CO$ has experienced a market drop In $\text{Calcutta}$ $\{(15 - 30) = -15\hspace{0.2cm} i.e \hspace{0.2cm}\dfrac{-15}{30}\times100 =\color{lightblue}{ 50\%}\}$ & $\text{Delhi}$ $\{(10 - 15) = -5\hspace{0.2cm} i.e \hspace{0.2cm}\dfrac{-5}{15}\times100 = \color{lightblue}{33.33\%}\}$.

The product $BN$ has experienced a market drop In $\text{Bombay}$ $\{(40 - 45) = -5\hspace{0.2cm} i.e \hspace{0.2cm}\dfrac{-5}{45}\times100 = \color{lightblue}{11.11\%}\}$ .

The product $MT$ has experienced a market drop In $\text{Madras}$ $\{(45 - 40) = -5\hspace{0.2cm} i.e \hspace{0.2cm}\dfrac{-5}{40}\times100 = \color{lightblue}{12.5\%}\}$ .

So, $\color{green}{\text{the largest percentage drop in market shares was experienced by}}$ $\color{gold}{CO}$ $\color{green}{in}$ $\color{red}{\text{Calcutta}}$ $\color{green}{\text{which was}}$ $\color{blue}{\dfrac{15-30}{30} \times 100 = \dfrac{-1}{2}\times100 = 50\%}$
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It is correct, but we need to find the % drop for each of them to be sure. Here, it just happened that the largest drop of 15 corresponded to the largest % drop.
0
Okay Sir.. thank you for mentioning , i'll update the answer
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