0 0 votes A value of $c$ for which the minimum value of $f(x)=x^{2}-4 c x+8 c$ is greater than the maximum value of $g(x)=-x^{2}+3 c x-2 c$, is$2$$\dfrac{1}{2}$$-\dfrac{1}{2}$$-2$ Others cat2025-set1 + – Shubham Sharma 2 4.7k points 121 views answer comment Share Follow Print 0 reply Please log in or register to add a comment.