0 0 votes Let $3 \leq x \leq 6$ and $\left[x^{2}\right]=[x]^{2}$, where $[x]$ is the greatest integer not exceeding $x$. If set $\mathrm{S}$ represents all feasible values of $x$, then a possible subset of $\mathrm{S}$ is$(3, \sqrt{10}) \cup[5, \sqrt{26}) \cup\{6\}$$\left[3, \sqrt{10}\right] \cup\left[5, \sqrt{26}\right]$$\left[3, \sqrt{10}\right] \cup \left[4, \sqrt{17}\right] \cup\{6\}$$(4, \sqrt{18}) \cup[5, \sqrt{27}) \cup\{6\}$ Others cat2025-set1 + – Shubham Sharma 2 4.7k points 131 views answer comment Share Follow Print 0 reply Please log in or register to add a comment.