0 votes 0 votes If $x^2 + y^2 = 0.1$ and $|x – y| = 0.2$, then $| x | + | y |$ is equal to $0.3$ $0.4$ $0.2$ $0.6$ Quantitative Aptitude cat2000 quantitative-aptitude absolute-value + – go_editor asked Mar 29, 2016 • edited Apr 14, 2022 by Lakshman Bhaiya go_editor 13.9k points 1.0k views answer comment Share See all 0 reply Please log in or register to add a comment.
0 votes 0 votes 0.4 Utkarsha Hajare answered Aug 7, 2019 Utkarsha Hajare 18 points comment Share See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Given, x$^2$+y$^2$=0.1 |x–y|=0.2 x$^2$+y$^2$=0.1= (x-y)$^2$-2xy 0.1= 0.04-2xy -2xy=0.06 xy= – 0.03 Checking the options, |x| and |y| can be 0.1 and 0.3 respectively which adds up to 0.4 sakharam answered Sep 4, 2019 sakharam 146 points comment Share See 1 comment See all 1 1 comment reply tskarthik 30 points commented Mar 12, 2023 reply Share $x+y= \sqrt{(x^2+y^2)+(2xy)}$ $=\sqrt{0.1+0.06}$ $=\sqrt{0.16}$ $=0.4$ 0 votes 0 votes Please log in or register to add a comment.