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$\mathrm{ABCD}$ is a trapezium in which $\mathrm{A B}$ is parallel to $\mathrm{C D}$. The sides $\mathrm{A D}$ and $\mathrm{B C}$ when extended, intersect at point $\mathrm{E}$.
If $\mathrm{A B}=2 \mathrm{~cm}, \mathrm{C D}=1 \mathrm{~cm}$, and perimeter of $\mathrm{A B C D}$ is $6 \: \mathrm{cm}$, then the perimeter, in $\mathrm{cm}$, of $\triangle \mathrm{A E B}$ is

  1. $8$
  2. $9$
  3. $7$
  4. $10$

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