0 0 votes The roots $\alpha, \beta$ of the equation $3 x^{2}+\lambda x-1=0$, satisfy $\frac{1}{\alpha^{2}}+\frac{1}{\beta^{2}}=15$. The value of $\left(\alpha^{3}+\beta^{3}\right)^{2}$, is$1$$4$$9$$16$ Others cat2024-set2 + – Shubham Sharma 2 3.9k points 486 views answer comment Share Follow Print 0 reply Please log in or register to add a comment.