2 2 votes For any natural numbers $\mathrm{m}, \mathrm{n}$, and $\mathrm{k}$, such that $\mathrm{k}$ divides both $m+2 n$ and $3 m+4 n \mathrm{k}$ must be a common divisor of$m$ and $n$$2 m$ and $3 n$$2 m$ and $n$$m$ and $2 n$ Quantitative Aptitude cat2023-set2 quantitative-aptitude number-systems + – admin 5.3k points 2.3k views answer comment Share Follow Print See 1 comment 1 1 comment reply pdevendra777 10 points commented Apr 22, 2025 reply Follow flag Please provide explanation 0 0 replyShare Please log in or register to add a comment.
0 0 votes C Gremaa9 answered Jul 6, 2024 Gremaa9 20 points comment Share Follow 0 reply Please log in or register to add a comment.