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For any natural numbers $\mathrm{m}, \mathrm{n}$, and $\mathrm{k}$, such that $\mathrm{k}$ divides both $m+2 n$ and $3 m+4 n \mathrm{k}$ must be a common divisor of

  1. $m$ and $n$
  2. $2 m$ and $3 n$
  3. $2 m$ and $n$
  4. $m$ and $2 n$

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