0 votes 0 votes Any non-zero real numbers $\mathrm{x}$, $\mathrm{y}$ such that $y \neq 3$ and $\frac{x}{y}<\frac{x+3}{y-3}$, will satisfy the condition $\frac{x}{y}<\frac{y}{x}$ If $y>10$, then $-x>y$ If $x<0$, then $-x If $y<0$, then $-x Others cat2023-set2 + – admin asked Mar 31 • edited Mar 31 by makhdoom ghaya admin 4.5k points 30 views answer comment Share See all 0 reply Please log in or register to add a comment.