0 votes 0 votes For any natural numbers $\mathrm{m}, \mathrm{n}$, and $\mathrm{k}$, such that $\mathrm{k}$ divides both $m+2 n$ and $3 m+4 n \mathrm{k}$ must be a common divisor of $m$ and $n$ $2 m$ and $3 n$ $2 m$ and $n$ $m$ and $2 n$ Others cat2023-set2 quantitative-aptitude + – admin asked Mar 31 • edited Mar 31 by makhdoom ghaya admin 4.5k points 66 views answer comment Share See all 0 reply Please log in or register to add a comment.