b is correct ans.
process to solve; fisrst let the quadratic equation be ax^2 + bx + c
and x=0 as it is given from here we found c=1.
and by putting x=1 we find a+b=2
now final task as clu is given in question that max at x=1 is three so we all know maxima happens at x= – b^2 /4a
so putting it into initial equation we find relation b^2 = -8a so now using this into a+b=2 we found a quaratic like
(b-4)^2=0 so b=4 and a=-2 by putting all these values in first we found -2x^2+4x+1.
hence at x=10 value is -159.
note: if u dont know quadratic equation maximum better use derivative concept of finding maxima and minima.