0 votes 0 votes Let $f(x) = \max (2x +1, 3 – 4x)$ where $x$ is any real number. Then the minimum possible value of $f(x)$ is: $1/3$ $1/2$ $2/3$ $4/3$ $5/3$ Quantitative Aptitude cat2006 quantitative-aptitude maxima-minima + – go_editor asked Dec 28, 2015 • edited Mar 29, 2022 by Lakshman Bhaiya go_editor 13.9k points 682 views answer comment Share See all 0 reply Please log in or register to add a comment.
Best answer 1 votes 1 votes Min of f(x) = min ( max ( 2x +1, 3 -4x) ) = 5/3., at x =1/3. Ans - 5. vijaycs answered Jul 30, 2016 • selected Jul 31, 2016 by Arjun vijaycs 1.5k points comment Share See all 0 reply Please log in or register to add a comment.