p1+p1=18 litre/min
leak pipeworks = 1/10 per min
tank filled in 15min , totalworkratepermin =1/15
(inletwork - leakagework)=totalworkratepermin
inlet work rate=totalworkratepermin + leakage work =(1/15)+(1/10)=1/6
therefore, inlet pipe fill at the rate (1/6)per min.i.e tank is filled in 6 min
speed of both inlet given=18litrepermin
Capacity of tank=6*18=108 liters.