0 votes 0 votes A quadrilateral $A B C D$ is inscribed in a circle such that $A B: C D=2: 1$ and $B C: A D=5: 4$. If $A C$ and $B D$ intersect at the point $E$, then $A E: C E$ equals $2: 1$ $5: 8$ $8: 5$ $1: 2$ Others cat2023-set1 + – admin asked Mar 30 • edited Mar 30 by makhdoom ghaya admin 4.5k points 47 views answer comment Share See all 0 reply Please log in or register to add a comment.